3(4c-2)-2=10c+8

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Solution for 3(4c-2)-2=10c+8 equation: 



3(4c-2)-2=10c+8

We move all terms to the left:

3(4c-2)-2-(10c+8)=0

We multiply parentheses

12c-(10c+8)-6-2=0

We get rid of parentheses

12c-10c-8-6-2=0

We add all the numbers together, and all the variables

2c-16=0

We move all terms containing c to the left, all other terms to the right

2c=16

c=16/2

c=8

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