3(4b-8)+2b=6(b-8)

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Solution for 3(4b-8)+2b=6(b-8) equation: 



3(4b-8)+2b=6(b-8)

We move all terms to the left:

3(4b-8)+2b-(6(b-8))=0

We add all the numbers together, and all the variables

2b+3(4b-8)-(6(b-8))=0

We multiply parentheses

2b+12b-(6(b-8))-24=0



We calculate terms in parentheses: -(6(b-8)), so:

6(b-8)

We multiply parentheses

6b-48

Back to the equation:

-(6b-48)



We add all the numbers together, and all the variables

14b-(6b-48)-24=0

We get rid of parentheses

14b-6b+48-24=0

We add all the numbers together, and all the variables

8b+24=0

We move all terms containing b to the left, all other terms to the right

8b=-24

b=-24/8

b=-3

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