3(4b-4)=-48

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Solution for 3(4b-4)=-48 equation: 



3(4b-4)=-48

We move all terms to the left:

3(4b-4)-(-48)=0

We add all the numbers together, and all the variables

3(4b-4)+48=0

We multiply parentheses

12b-12+48=0

We add all the numbers together, and all the variables

12b+36=0

We move all terms containing b to the left, all other terms to the right

12b=-36

b=-36/12

b=-3

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