3(4b-2c)+8+7c=

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Solution for 3(4b-2c)+8+7c= equation:


Simplifying
3(4b + -2c) + 8 + 7c = 0
(4b * 3 + -2c * 3) + 8 + 7c = 0
(12b + -6c) + 8 + 7c = 0

Reorder the terms:
8 + 12b + -6c + 7c = 0

Combine like terms: -6c + 7c = 1c
8 + 12b + 1c = 0

Solving
8 + 12b + 1c = 0

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + 12b + -8 + 1c = 0 + -8

Reorder the terms:
8 + -8 + 12b + 1c = 0 + -8

Combine like terms: 8 + -8 = 0
0 + 12b + 1c = 0 + -8
12b + 1c = 0 + -8

Combine like terms: 0 + -8 = -8
12b + 1c = -8

Add '-1c' to each side of the equation.
12b + 1c + -1c = -8 + -1c

Combine like terms: 1c + -1c = 0
12b + 0 = -8 + -1c
12b = -8 + -1c

Divide each side by '12'.
b = -0.6666666667 + -0.08333333333c

Simplifying
b = -0.6666666667 + -0.08333333333c

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