3(4b+5)=9b+17

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Solution for 3(4b+5)=9b+17 equation: 



3(4b+5)=9b+17

We move all terms to the left:

3(4b+5)-(9b+17)=0

We multiply parentheses

12b-(9b+17)+15=0

We get rid of parentheses

12b-9b-17+15=0

We add all the numbers together, and all the variables

3b-2=0

We move all terms containing b to the left, all other terms to the right

3b=2

b=2/3

b=2/3

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