3(4b+1)-b=2(2b+5)

Solution for 3(4b+1)-b=2(2b+5) equation:

Simplifying
3(4b + 1) + -1b = 2(2b + 5)

Reorder the terms:
3(1 + 4b) + -1b = 2(2b + 5)
(1 * 3 + 4b * 3) + -1b = 2(2b + 5)
(3 + 12b) + -1b = 2(2b + 5)

Combine like terms: 12b + -1b = 11b
3 + 11b = 2(2b + 5)

Reorder the terms:
3 + 11b = 2(5 + 2b)
3 + 11b = (5 * 2 + 2b * 2)
3 + 11b = (10 + 4b)

Solving
3 + 11b = 10 + 4b

Solving for variable 'b'.

Move all terms containing b to the left, all other terms to the right.

Add '-4b' to each side of the equation.
3 + 11b + -4b = 10 + 4b + -4b

Combine like terms: 11b + -4b = 7b
3 + 7b = 10 + 4b + -4b

Combine like terms: 4b + -4b = 0
3 + 7b = 10 + 0
3 + 7b = 10

Add '-3' to each side of the equation.
3 + -3 + 7b = 10 + -3

Combine like terms: 3 + -3 = 0
0 + 7b = 10 + -3
7b = 10 + -3

Combine like terms: 10 + -3 = 7
7b = 7

Divide each side by '7'.
b = 1

Simplifying
b = 1