3(4a-2-a+7)=6(7+2a)

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Solution for 3(4a-2-a+7)=6(7+2a) equation: 



3(4a-2-a+7)=6(7+2a)

We move all terms to the left:

3(4a-2-a+7)-(6(7+2a))=0

We add all the numbers together, and all the variables

3(3a+5)-(6(2a+7))=0

We multiply parentheses

9a-(6(2a+7))+15=0



We calculate terms in parentheses: -(6(2a+7)), so:

6(2a+7)

We multiply parentheses

12a+42

Back to the equation:

-(12a+42)



We get rid of parentheses

9a-12a-42+15=0

We add all the numbers together, and all the variables

-3a-27=0

We move all terms containing a to the left, all other terms to the right

-3a=27

a=27/-3

a=-9

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