3(4a+12)=2(a-2)

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Solution for 3(4a+12)=2(a-2) equation: 



3(4a+12)=2(a-2)

We move all terms to the left:

3(4a+12)-(2(a-2))=0

We multiply parentheses

12a-(2(a-2))+36=0



We calculate terms in parentheses: -(2(a-2)), so:

2(a-2)

We multiply parentheses

2a-4

Back to the equation:

-(2a-4)



We get rid of parentheses

12a-2a+4+36=0

We add all the numbers together, and all the variables

10a+40=0

We move all terms containing a to the left, all other terms to the right

10a=-40

a=-40/10

a=-4

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