3(4B-7)=2(3b+11)=5

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Solution for 3(4B-7)=2(3b+11)=5 equation: 



3(4-7)=2(3B+11)=5

We move all terms to the left:

3(4-7)-(2(3B+11))=0

We add all the numbers together, and all the variables

-(2(3B+11))+3(-3)=0

We add all the numbers together, and all the variables

-(2(3B+11))-9=0



We calculate terms in parentheses: -(2(3B+11)), so:

2(3B+11)

We multiply parentheses

6B+22

Back to the equation:

-(6B+22)



We get rid of parentheses

-6B-22-9=0

We add all the numbers together, and all the variables

-6B-31=0

We move all terms containing B to the left, all other terms to the right

-6B=31

B=31/-6

B=-5+1/6

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