3(41-7)=2(10+g)

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Solution for 3(41-7)=2(10+g) equation: 



3(41-7)=2(10+g)

We move all terms to the left:

3(41-7)-(2(10+g))=0

We add all the numbers together, and all the variables

-(2(g+10))+334=0



We calculate terms in parentheses: -(2(g+10)), so:

2(g+10)

We multiply parentheses

2g+20

Back to the equation:

-(2g+20)



We get rid of parentheses

-2g-20+334=0

We add all the numbers together, and all the variables

-2g+314=0

We move all terms containing g to the left, all other terms to the right

-2g=-314

g=-314/-2

g=+157

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