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3(4/5z-2)=-12
We move all terms to the left:
3(4/5z-2)-(-12)=0
Domain of the equation: 5z-2)!=0We add all the numbers together, and all the variables
z∈R
3(4/5z-2)+12=0
We multiply parentheses
12z-6+12=0
We add all the numbers together, and all the variables
12z+6=0
We move all terms containing z to the left, all other terms to the right
12z=-6
z=-6/12
z=-1/2
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