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3(4-x)=10(x+5)
We move all terms to the left:
3(4-x)-(10(x+5))=0
We add all the numbers together, and all the variables
3(-1x+4)-(10(x+5))=0
We multiply parentheses
-3x-(10(x+5))+12=0
We calculate terms in parentheses: -(10(x+5)), so:We get rid of parentheses
10(x+5)
We multiply parentheses
10x+50
Back to the equation:
-(10x+50)
-3x-10x-50+12=0
We add all the numbers together, and all the variables
-13x-38=0
We move all terms containing x to the left, all other terms to the right
-13x=38
x=38/-13
x=-2+12/13
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