3(4-a)=a+40

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Solution for 3(4-a)=a+40 equation: 



3(4-a)=a+40

We move all terms to the left:

3(4-a)-(a+40)=0

We add all the numbers together, and all the variables

3(-1a+4)-(a+40)=0

We multiply parentheses

-3a-(a+40)+12=0

We get rid of parentheses

-3a-a-40+12=0

We add all the numbers together, and all the variables

-4a-28=0

We move all terms containing a to the left, all other terms to the right

-4a=28

a=28/-4

a=-7

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