3(4-a)=3(a-19)

Solution for 3(4-a)=3(a-19) equation:

3(4-a)=3(a-19)

We move all terms to the left:

3(4-a)-(3(a-19))=0

We add all the numbers together, and all the variables

3(-1a+4)-(3(a-19))=0

We multiply parentheses

-3a-(3(a-19))+12=0


We calculate terms in parentheses: -(3(a-19)), so:

3(a-19)

We multiply parentheses

3a-57

Back to the equation:

-(3a-57)


We get rid of parentheses

-3a-3a+57+12=0

We add all the numbers together, and all the variables

-6a+69=0

We move all terms containing a to the left, all other terms to the right

-6a=-69

a=-69/-6

a=11+1/2