3(4-3x)5+(-2x+4x)=9x-20

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Solution for 3(4-3x)5+(-2x+4x)=9x-20 equation: 



3(4-3x)5+(-2x+4x)=9x-20

We move all terms to the left:

3(4-3x)5+(-2x+4x)-(9x-20)=0

We add all the numbers together, and all the variables

3(-3x+4)5+(+2x)-(9x-20)=0

We multiply parentheses

-45x+(+2x)-(9x-20)+60=0

We get rid of parentheses

-45x+2x-9x+20+60=0

We add all the numbers together, and all the variables

-52x+80=0

We move all terms containing x to the left, all other terms to the right

-52x=-80

x=-80/-52

x=1+7/13

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