3(4-2x)=4(x-2)

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Solution for 3(4-2x)=4(x-2) equation: 



3(4-2x)=4(x-2)

We move all terms to the left:

3(4-2x)-(4(x-2))=0

We add all the numbers together, and all the variables

3(-2x+4)-(4(x-2))=0

We multiply parentheses

-6x-(4(x-2))+12=0



We calculate terms in parentheses: -(4(x-2)), so:

4(x-2)

We multiply parentheses

4x-8

Back to the equation:

-(4x-8)



We get rid of parentheses

-6x-4x+8+12=0

We add all the numbers together, and all the variables

-10x+20=0

We move all terms containing x to the left, all other terms to the right

-10x=-20

x=-20/-10

x=+2

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