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3(4-2x)=2(2x-3)
We move all terms to the left:
3(4-2x)-(2(2x-3))=0
We add all the numbers together, and all the variables
3(-2x+4)-(2(2x-3))=0
We multiply parentheses
-6x-(2(2x-3))+12=0
We calculate terms in parentheses: -(2(2x-3)), so:We get rid of parentheses
2(2x-3)
We multiply parentheses
4x-6
Back to the equation:
-(4x-6)
-6x-4x+6+12=0
We add all the numbers together, and all the variables
-10x+18=0
We move all terms containing x to the left, all other terms to the right
-10x=-18
x=-18/-10
x=1+4/5
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