3(4-2n)=-6(n-2)

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Solution for 3(4-2n)=-6(n-2) equation: 



3(4-2n)=-6(n-2)

We move all terms to the left:

3(4-2n)-(-6(n-2))=0

We add all the numbers together, and all the variables

3(-2n+4)-(-6(n-2))=0

We multiply parentheses

-6n-(-6(n-2))+12=0



We calculate terms in parentheses: -(-6(n-2)), so:

-6(n-2)

We multiply parentheses

-6n+12

Back to the equation:

-(-6n+12)



We get rid of parentheses

-6n+6n-12+12=0

We add all the numbers together, and all the variables

=0

n=0/1

n=0

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