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3(4+x-3)=2(x+4)+x*
We move all terms to the left:
3(4+x-3)-(2(x+4)+x*)=0
We add all the numbers together, and all the variables
3(x+1)-(2(x+4)+x*)=0
We multiply parentheses
3x-(2(x+4)+x*)+3=0
We calculate terms in parentheses: -(2(x+4)+x*), so:We get rid of parentheses
2(x+4)+x*
We multiply parentheses
2x+x*+8
Back to the equation:
-(2x+x*+8)
3x-2x-x*-8+3=0
We add all the numbers together, and all the variables
x-x*-5=0
We move all terms containing x to the left, all other terms to the right
x-x*=5
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