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3(4+x-3)=2(x+4)+x
We move all terms to the left:
3(4+x-3)-(2(x+4)+x)=0
We add all the numbers together, and all the variables
3(x+1)-(2(x+4)+x)=0
We multiply parentheses
3x-(2(x+4)+x)+3=0
We calculate terms in parentheses: -(2(x+4)+x), so:We get rid of parentheses
2(x+4)+x
We add all the numbers together, and all the variables
x+2(x+4)
We multiply parentheses
x+2x+8
We add all the numbers together, and all the variables
3x+8
Back to the equation:
-(3x+8)
3x-3x-8+3=0
We add all the numbers together, and all the variables
-5!=0
There is no solution for this equation
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