3(4+x)=(x+4)+1-3x

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Solution for 3(4+x)=(x+4)+1-3x equation: 



3(4+x)=(x+4)+1-3x

We move all terms to the left:

3(4+x)-((x+4)+1-3x)=0

We add all the numbers together, and all the variables

3(x+4)-((x+4)+1-3x)=0

We multiply parentheses

3x-((x+4)+1-3x)+12=0



We calculate terms in parentheses: -((x+4)+1-3x), so:

(x+4)+1-3x

determiningTheFunctionDomain
(x+4)-3x+1

We add all the numbers together, and all the variables

-3x+(x+4)+1

We get rid of parentheses

-3x+x+4+1

We add all the numbers together, and all the variables

-2x+5

Back to the equation:

-(-2x+5)



We get rid of parentheses

3x+2x-5+12=0

We add all the numbers together, and all the variables

5x+7=0

We move all terms containing x to the left, all other terms to the right

5x=-7

x=-7/5

x=-1+2/5

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