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3(4+x)-2(3x+4)=5(x-3)-(8x-19)
We move all terms to the left:
3(4+x)-2(3x+4)-(5(x-3)-(8x-19))=0
We add all the numbers together, and all the variables
3(x+4)-2(3x+4)-(5(x-3)-(8x-19))=0
We multiply parentheses
3x-6x-(5(x-3)-(8x-19))+12-8=0
We calculate terms in parentheses: -(5(x-3)-(8x-19)), so:We add all the numbers together, and all the variables
5(x-3)-(8x-19)
We multiply parentheses
5x-(8x-19)-15
We get rid of parentheses
5x-8x+19-15
We add all the numbers together, and all the variables
-3x+4
Back to the equation:
-(-3x+4)
-3x-(-3x+4)+4=0
We get rid of parentheses
-3x+3x-4+4=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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