3(4+e)=33,e=

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Solution for 3(4+e)=33,e= equation: 



3(4+e)=33.e=

We move all terms to the left:

3(4+e)-(33.e)=0

We add all the numbers together, and all the variables

3(e+4)-(+33.e)=0

We multiply parentheses

3e-(+33.e)+12=0

We get rid of parentheses

3e-33.e+12=0

We add all the numbers together, and all the variables

-30e+12=0

We move all terms containing e to the left, all other terms to the right

-30e=-12

e=-12/-30

e=2/5

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