3(4+3r)=3(r+1)+11

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Solution for 3(4+3r)=3(r+1)+11 equation: 



3(4+3r)=3(r+1)+11

We move all terms to the left:

3(4+3r)-(3(r+1)+11)=0

We add all the numbers together, and all the variables

3(3r+4)-(3(r+1)+11)=0

We multiply parentheses

9r-(3(r+1)+11)+12=0



We calculate terms in parentheses: -(3(r+1)+11), so:

3(r+1)+11

We multiply parentheses

3r+3+11

We add all the numbers together, and all the variables

3r+14

Back to the equation:

-(3r+14)



We get rid of parentheses

9r-3r-14+12=0

We add all the numbers together, and all the variables

6r-2=0

We move all terms containing r to the left, all other terms to the right

6r=2

r=2/6

r=1/3

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