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3(4+2x)=15(x+1)-12
We move all terms to the left:
3(4+2x)-(15(x+1)-12)=0
We add all the numbers together, and all the variables
3(2x+4)-(15(x+1)-12)=0
We multiply parentheses
6x-(15(x+1)-12)+12=0
We calculate terms in parentheses: -(15(x+1)-12), so:We get rid of parentheses
15(x+1)-12
We multiply parentheses
15x+15-12
We add all the numbers together, and all the variables
15x+3
Back to the equation:
-(15x+3)
6x-15x-3+12=0
We add all the numbers together, and all the variables
-9x+9=0
We move all terms containing x to the left, all other terms to the right
-9x=-9
x=-9/-9
x=1
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