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3(4+2x)+x=2(x-1)-1
We move all terms to the left:
3(4+2x)+x-(2(x-1)-1)=0
We add all the numbers together, and all the variables
3(2x+4)+x-(2(x-1)-1)=0
We add all the numbers together, and all the variables
x+3(2x+4)-(2(x-1)-1)=0
We multiply parentheses
x+6x-(2(x-1)-1)+12=0
We calculate terms in parentheses: -(2(x-1)-1), so:We add all the numbers together, and all the variables
2(x-1)-1
We multiply parentheses
2x-2-1
We add all the numbers together, and all the variables
2x-3
Back to the equation:
-(2x-3)
7x-(2x-3)+12=0
We get rid of parentheses
7x-2x+3+12=0
We add all the numbers together, and all the variables
5x+15=0
We move all terms containing x to the left, all other terms to the right
5x=-15
x=-15/5
x=-3
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