3(4+2n)+7n=36+n

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Solution for 3(4+2n)+7n=36+n equation: 



3(4+2n)+7n=36+n

We move all terms to the left:

3(4+2n)+7n-(36+n)=0

We add all the numbers together, and all the variables

3(2n+4)+7n-(n+36)=0

We add all the numbers together, and all the variables

7n+3(2n+4)-(n+36)=0

We multiply parentheses

7n+6n-(n+36)+12=0

We get rid of parentheses

7n+6n-n-36+12=0

We add all the numbers together, and all the variables

12n-24=0

We move all terms containing n to the left, all other terms to the right

12n=24

n=24/12

n=2

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