3(3z-5)=4(2-z)

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Solution for 3(3z-5)=4(2-z) equation: 



3(3z-5)=4(2-z)

We move all terms to the left:

3(3z-5)-(4(2-z))=0

We add all the numbers together, and all the variables

3(3z-5)-(4(-1z+2))=0

We multiply parentheses

9z-(4(-1z+2))-15=0



We calculate terms in parentheses: -(4(-1z+2)), so:

4(-1z+2)

We multiply parentheses

-4z+8

Back to the equation:

-(-4z+8)



We get rid of parentheses

9z+4z-8-15=0

We add all the numbers together, and all the variables

13z-23=0

We move all terms containing z to the left, all other terms to the right

13z=23

z=23/13

z=1+10/13

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