3(3z+3)=3-2(z-3)

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Solution for 3(3z+3)=3-2(z-3) equation: 



3(3z+3)=3-2(z-3)

We move all terms to the left:

3(3z+3)-(3-2(z-3))=0

We multiply parentheses

9z-(3-2(z-3))+9=0



We calculate terms in parentheses: -(3-2(z-3)), so:

3-2(z-3)

determiningTheFunctionDomain
-2(z-3)+3

We multiply parentheses

-2z+6+3

We add all the numbers together, and all the variables

-2z+9

Back to the equation:

-(-2z+9)



We get rid of parentheses

9z+2z-9+9=0

We add all the numbers together, and all the variables

11z=0

z=0/11

z=0

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