3(3z+2)=2z+27

Solution for 3(3z+2)=2z+27 equation:

Simplifying
3(3z + 2) = 2z + 27

Reorder the terms:
3(2 + 3z) = 2z + 27
(2 * 3 + 3z * 3) = 2z + 27
(6 + 9z) = 2z + 27

Reorder the terms:
6 + 9z = 27 + 2z

Solving
6 + 9z = 27 + 2z

Solving for variable 'z'.

Move all terms containing z to the left, all other terms to the right.

Add '-2z' to each side of the equation.
6 + 9z + -2z = 27 + 2z + -2z

Combine like terms: 9z + -2z = 7z
6 + 7z = 27 + 2z + -2z

Combine like terms: 2z + -2z = 0
6 + 7z = 27 + 0
6 + 7z = 27

Add '-6' to each side of the equation.
6 + -6 + 7z = 27 + -6

Combine like terms: 6 + -6 = 0
0 + 7z = 27 + -6
7z = 27 + -6

Combine like terms: 27 + -6 = 21
7z = 21

Divide each side by '7'.
z = 3

Simplifying
z = 3