3(3z+2)=12

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Solution for 3(3z+2)=12 equation: 



3(3z+2)=12

We move all terms to the left:

3(3z+2)-(12)=0

We multiply parentheses

9z+6-12=0

We add all the numbers together, and all the variables

9z-6=0

We move all terms containing z to the left, all other terms to the right

9z=6

z=6/9

z=2/3

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