3(3z+10)=21z=-1

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Solution for 3(3z+10)=21z=-1 equation: 



3(3z+10)=21z=-1

We move all terms to the left:

3(3z+10)-(21z)=0

We add all the numbers together, and all the variables

-21z+3(3z+10)=0

We multiply parentheses

-21z+9z+30=0

We add all the numbers together, and all the variables

-12z+30=0

We move all terms containing z to the left, all other terms to the right

-12z=-30

z=-30/-12

z=2+1/2

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