3(3y-8)=-2(y-4)+3y

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Solution for 3(3y-8)=-2(y-4)+3y equation: 



3(3y-8)=-2(y-4)+3y

We move all terms to the left:

3(3y-8)-(-2(y-4)+3y)=0

We multiply parentheses

9y-(-2(y-4)+3y)-24=0



We calculate terms in parentheses: -(-2(y-4)+3y), so:

-2(y-4)+3y

We add all the numbers together, and all the variables

3y-2(y-4)

We multiply parentheses

3y-2y+8

We add all the numbers together, and all the variables

y+8

Back to the equation:

-(y+8)



We get rid of parentheses

9y-y-8-24=0

We add all the numbers together, and all the variables

8y-32=0

We move all terms containing y to the left, all other terms to the right

8y=32

y=32/8

y=4

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