3(3y-7)+4y=31

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Solution for 3(3y-7)+4y=31 equation: 



3(3y-7)+4y=31

We move all terms to the left:

3(3y-7)+4y-(31)=0

We add all the numbers together, and all the variables

4y+3(3y-7)-31=0

We multiply parentheses

4y+9y-21-31=0

We add all the numbers together, and all the variables

13y-52=0

We move all terms containing y to the left, all other terms to the right

13y=52

y=52/13

y=4

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