3(3y-5)=38

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Solution for 3(3y-5)=38 equation:



3(3y-5)=38
We move all terms to the left:
3(3y-5)-(38)=0
We multiply parentheses
9y-15-38=0
We add all the numbers together, and all the variables
9y-53=0
We move all terms containing y to the left, all other terms to the right
9y=53
y=53/9
y=5+8/9

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