3(3y+6)+2y=7

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Solution for 3(3y+6)+2y=7 equation: 



3(3y+6)+2y=7

We move all terms to the left:

3(3y+6)+2y-(7)=0

We add all the numbers together, and all the variables

2y+3(3y+6)-7=0

We multiply parentheses

2y+9y+18-7=0

We add all the numbers together, and all the variables

11y+11=0

We move all terms containing y to the left, all other terms to the right

11y=-11

y=-11/11

y=-1

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