3(3y+3y)=12

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Solution for 3(3y+3y)=12 equation: 



3(3y+3y)=12

We move all terms to the left:

3(3y+3y)-(12)=0

We add all the numbers together, and all the variables

3(+6y)-12=0

We multiply parentheses

18y-12=0

We move all terms containing y to the left, all other terms to the right

18y=12

y=12/18

y=2/3

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