3(3y+12)+3y=0

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Solution for 3(3y+12)+3y=0 equation: 



3(3y+12)+3y=0

We add all the numbers together, and all the variables

3y+3(3y+12)=0

We multiply parentheses

3y+9y+36=0

We add all the numbers together, and all the variables

12y+36=0

We move all terms containing y to the left, all other terms to the right

12y=-36

y=-36/12

y=-3

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