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3(3x-9)-2=3(x-3)+34
We move all terms to the left:
3(3x-9)-2-(3(x-3)+34)=0
We multiply parentheses
9x-(3(x-3)+34)-27-2=0
We calculate terms in parentheses: -(3(x-3)+34), so:We add all the numbers together, and all the variables
3(x-3)+34
We multiply parentheses
3x-9+34
We add all the numbers together, and all the variables
3x+25
Back to the equation:
-(3x+25)
9x-(3x+25)-29=0
We get rid of parentheses
9x-3x-25-29=0
We add all the numbers together, and all the variables
6x-54=0
We move all terms containing x to the left, all other terms to the right
6x=54
x=54/6
x=9
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