3(3x-7)-4=3(x-2)+35

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Solution for 3(3x-7)-4=3(x-2)+35 equation: 



3(3x-7)-4=3(x-2)+35

We move all terms to the left:

3(3x-7)-4-(3(x-2)+35)=0

We multiply parentheses

9x-(3(x-2)+35)-21-4=0



We calculate terms in parentheses: -(3(x-2)+35), so:

3(x-2)+35

We multiply parentheses

3x-6+35

We add all the numbers together, and all the variables

3x+29

Back to the equation:

-(3x+29)



We add all the numbers together, and all the variables

9x-(3x+29)-25=0

We get rid of parentheses

9x-3x-29-25=0

We add all the numbers together, and all the variables

6x-54=0

We move all terms containing x to the left, all other terms to the right

6x=54

x=54/6

x=9

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