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3(3x-5)=-11(2x+7)
We move all terms to the left:
3(3x-5)-(-11(2x+7))=0
We multiply parentheses
9x-(-11(2x+7))-15=0
We calculate terms in parentheses: -(-11(2x+7)), so:We get rid of parentheses
-11(2x+7)
We multiply parentheses
-22x-77
Back to the equation:
-(-22x-77)
9x+22x+77-15=0
We add all the numbers together, and all the variables
31x+62=0
We move all terms containing x to the left, all other terms to the right
31x=-62
x=-62/31
x=-2
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