3(3x-5)+3(x+2)=2(x+10)-(x+10)

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Solution for 3(3x-5)+3(x+2)=2(x+10)-(x+10) equation: 



3(3x-5)+3(x+2)=2(x+10)-(x+10)

We move all terms to the left:

3(3x-5)+3(x+2)-(2(x+10)-(x+10))=0

We multiply parentheses

9x+3x-(2(x+10)-(x+10))-15+6=0



We calculate terms in parentheses: -(2(x+10)-(x+10)), so:

2(x+10)-(x+10)

We multiply parentheses

2x-(x+10)+20

We get rid of parentheses

2x-x-10+20

We add all the numbers together, and all the variables

x+10

Back to the equation:

-(x+10)



We add all the numbers together, and all the variables

12x-(x+10)-9=0

We get rid of parentheses

12x-x-10-9=0

We add all the numbers together, and all the variables

11x-19=0

We move all terms containing x to the left, all other terms to the right

11x=19

x=19/11

x=1+8/11

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