3(3x-4)=1/4(32x

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Solution for 3(3x-4)=1/4(32x equation: 



3(3x-4)=1/4(32x

We move all terms to the left:

3(3x-4)-(1/4(32x)=0



Domain of the equation: 432x!=0

x!=0/432

x!=0

x∈R



We multiply parentheses

9x-(1/432x-12=0

We multiply all the terms by the denominator


9x*432x-12-(1=0

We add all the numbers together, and all the variables

9x*432x=0

Wy multiply elements

3888x^2=0

a = 3888; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·3888·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{0}{7776}=0$

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