3(3x-4)+6(7-x)=5x+(2x-3)

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Solution for 3(3x-4)+6(7-x)=5x+(2x-3) equation: 



3(3x-4)+6(7-x)=5x+(2x-3)

We move all terms to the left:

3(3x-4)+6(7-x)-(5x+(2x-3))=0

We add all the numbers together, and all the variables

3(3x-4)+6(-1x+7)-(5x+(2x-3))=0

We multiply parentheses

9x-6x-(5x+(2x-3))-12+42=0



We calculate terms in parentheses: -(5x+(2x-3)), so:

5x+(2x-3)

We get rid of parentheses

5x+2x-3

We add all the numbers together, and all the variables

7x-3

Back to the equation:

-(7x-3)



We add all the numbers together, and all the variables

3x-(7x-3)+30=0

We get rid of parentheses

3x-7x+3+30=0

We add all the numbers together, and all the variables

-4x+33=0

We move all terms containing x to the left, all other terms to the right

-4x=-33

x=-33/-4

x=8+1/4

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