3(3x-35)=2(x+28)

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Solution for 3(3x-35)=2(x+28) equation: 



3(3x-35)=2(x+28)

We move all terms to the left:

3(3x-35)-(2(x+28))=0

We multiply parentheses

9x-(2(x+28))-105=0



We calculate terms in parentheses: -(2(x+28)), so:

2(x+28)

We multiply parentheses

2x+56

Back to the equation:

-(2x+56)



We get rid of parentheses

9x-2x-56-105=0

We add all the numbers together, and all the variables

7x-161=0

We move all terms containing x to the left, all other terms to the right

7x=161

x=161/7

x=23

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