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3(3x-3)-5=3(x-2)+22
We move all terms to the left:
3(3x-3)-5-(3(x-2)+22)=0
We multiply parentheses
9x-(3(x-2)+22)-9-5=0
We calculate terms in parentheses: -(3(x-2)+22), so:We add all the numbers together, and all the variables
3(x-2)+22
We multiply parentheses
3x-6+22
We add all the numbers together, and all the variables
3x+16
Back to the equation:
-(3x+16)
9x-(3x+16)-14=0
We get rid of parentheses
9x-3x-16-14=0
We add all the numbers together, and all the variables
6x-30=0
We move all terms containing x to the left, all other terms to the right
6x=30
x=30/6
x=5
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