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3(3x-2)=3(2x-3)
We move all terms to the left:
3(3x-2)-(3(2x-3))=0
We multiply parentheses
9x-(3(2x-3))-6=0
We calculate terms in parentheses: -(3(2x-3)), so:We get rid of parentheses
3(2x-3)
We multiply parentheses
6x-9
Back to the equation:
-(6x-9)
9x-6x+9-6=0
We add all the numbers together, and all the variables
3x+3=0
We move all terms containing x to the left, all other terms to the right
3x=-3
x=-3/3
x=-1
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