3(3x-2)=2x+16

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Solution for 3(3x-2)=2x+16 equation: 



3(3x-2)=2x+16

We move all terms to the left:

3(3x-2)-(2x+16)=0

We multiply parentheses

9x-(2x+16)-6=0

We get rid of parentheses

9x-2x-16-6=0

We add all the numbers together, and all the variables

7x-22=0

We move all terms containing x to the left, all other terms to the right

7x=22

x=22/7

x=3+1/7

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