3(3x-2)-3=3(x-3)+24

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Solution for 3(3x-2)-3=3(x-3)+24 equation: 



3(3x-2)-3=3(x-3)+24

We move all terms to the left:

3(3x-2)-3-(3(x-3)+24)=0

We multiply parentheses

9x-(3(x-3)+24)-6-3=0



We calculate terms in parentheses: -(3(x-3)+24), so:

3(x-3)+24

We multiply parentheses

3x-9+24

We add all the numbers together, and all the variables

3x+15

Back to the equation:

-(3x+15)



We add all the numbers together, and all the variables

9x-(3x+15)-9=0

We get rid of parentheses

9x-3x-15-9=0

We add all the numbers together, and all the variables

6x-24=0

We move all terms containing x to the left, all other terms to the right

6x=24

x=24/6

x=4

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