3(3x-1)-5(4x-2)+9+5(2-x)=15

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Solution for 3(3x-1)-5(4x-2)+9+5(2-x)=15 equation: 



3(3x-1)-5(4x-2)+9+5(2-x)=15

We move all terms to the left:

3(3x-1)-5(4x-2)+9+5(2-x)-(15)=0

We add all the numbers together, and all the variables

3(3x-1)-5(4x-2)+5(-1x+2)+9-15=0

We add all the numbers together, and all the variables

3(3x-1)-5(4x-2)+5(-1x+2)-6=0

We multiply parentheses

9x-20x-5x-3+10+10-6=0

We add all the numbers together, and all the variables

-16x+11=0

We move all terms containing x to the left, all other terms to the right

-16x=-11

x=-11/-16

x=11/16

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